\(=3\left(\dfrac{1}{2}+\dfrac{1}{5}\right)=3\cdot\dfrac{7}{10}=\dfrac{21}{10}\)
\(\dfrac{3}{2}+\dfrac{3}{5}=\dfrac{15}{10}+\dfrac{6}{10}=\dfrac{21}{10}\)
Đây bạn!!!
\(\dfrac{3}{2}+\dfrac{3}{5}\)
= \(\dfrac{15}{10}+\dfrac{6}{10}\)
= \(\dfrac{21}{10}\)
= 2,1
\(\dfrac{3}{2}\) + \(\dfrac{3}{5}\)= \(\dfrac{15}{10}\)+\(\dfrac{6}{10}\)=\(\dfrac{21}{10}\)