[3^17.81^11]/[27^10.9^15]
=[3^17.(3^4)^11]/[(3^3)^10.(3^2)^15]
=[3^17.3^44]/[3^30.3^30]
=3^61/3^60
=3
\(\frac{3^{17}.81^{11}}{27^{10}.9^{15}}\)
\(=\)\(\frac{3^{17}.\left(3^4\right)^{11}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}\)
\(=\)\(\frac{3^{17}.3^{44}}{3^{30}.3^{30}}\)
\(=\)\(\frac{3^{61}}{3^{60}}\)
\(=\)\(3\)