`3^(2x-1.3)=3`
`3^(2x-3)=3^1`
`2x-3=1`
`2x=4`
`x=4/2`
`x=2`
`3^(2x-1) . 3 = 3`
`=> 3^(2x-1) = 3 : 3`
`=> 3^(2x-1) = 1`
`=> 3^(2x-1) = 3^0`
`=> 2x-1 = 0`
`=> 2x = 0 +1`
`=> 2x = 1`
`=> x = 1/2`
32.x-1.3=3
=>32.x-1=3:3
=>32.x-1=1
=>32.x-1=30
=>2.x-1=0
=>2.x=1
=>x=\(\dfrac{1}{2}\)
Vậy x=\(\dfrac{1}{2}\)
`3^(2x-1).3=3`
`=> 3^(2x-1)=3:3`
`=> 3^(2x-1)=1`
`=>3^(2x-1)=3^0`
`=> 2x-1=0`
`=> 2x=0+1`
`=> 2x=1`
`=>x=1/2`