\(\left(3\frac{4}{7}+2\frac{3}{7}\right)+2\frac{2}{5}=6+2\frac{2}{5}=8\frac{2}{5}\)
\(3\frac{4}{7}+2\frac{2}{5}+2\frac{3}{7}=3+\frac{4}{7}+2+\frac{2}{5}+2+\frac{3}{7}\)
\(=\left(3+2+2\right)+\left(\frac{4}{7}+\frac{3}{7}\right)+\frac{2}{5}=7+1+\frac{2}{5}=8\frac{2}{5}\)