\(\frac{3}{1.4}+\frac{3}{4.7}+....+\frac{3}{40.43}+\frac{3}{43.46}\)
=\(3-\frac{3}{4}+\frac{3}{4}-\frac{3}{7}+.....+\frac{3}{43}-\frac{3}{46}\)
=\(3-\frac{3}{46}=\frac{138}{46}-\frac{3}{46}=\frac{135}{46}\)
\(\frac{3}{1.4}+\frac{3}{4.7}+.....+\frac{3}{40.43}+\frac{3}{43.46}\)
=\(3-\frac{3}{4}+\frac{3}{4}-\frac{3}{7}+.....+\frac{3}{43}-\frac{3}{46}\)
=\(3-\frac{3}{46}=\frac{138}{46}-\frac{3}{46}=\frac{135}{46}\)