\(3-\dfrac{2}{2x-3}=\dfrac{2}{5}+\dfrac{2}{9-6x}-\dfrac{3}{2}\)
\(\Leftrightarrow\dfrac{6x-9-2}{2x-3}=-\dfrac{11}{10}-\dfrac{2}{3\left(2x-3\right)}\)
\(\Leftrightarrow30\left(6x-11\right)=-33\left(2x-3\right)-20\)
=>180x-330=-66x+99-20
=>246x=409
hay x=409/246