3 . 22 - | x - 3 | = 10
\(3 . 2^2 - x + 3 = 10\)
\(15-x=10\)
\(x=15-10\)
\(x=5\)
Vậy `x=5`
\(3.2^2-\left|x-3\right|=10\\ \Rightarrow3.4-\left|x-3\right|=10\\ \Rightarrow12-\left|x-3\right|=10\\ \Rightarrow\left|x-3\right|=2\\ \Rightarrow\left[{}\begin{matrix}x-3=2\\x-3=-2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\x=-1\end{matrix}\right.\)