\(\left(3\dfrac{1}{2}+2y\right).2\dfrac{2}{3}=5\dfrac{1}{3}\)
<=> \(\left(\dfrac{7}{2}+2y\right).\dfrac{8}{3}=\dfrac{16}{3}\)
<=> \(\dfrac{7}{2}+2y=\dfrac{1}{2}\)
<=> 2y = -3
<=> y = \(\dfrac{-3}{2}\)
(Lưu ý: nếu bn muốn đánh \(a\dfrac{b}{c}\) mà ko viết đc thì bn nên viết \(a+\dfrac{b}{c}\) vì \(a+\dfrac{b}{c}=a\dfrac{b}{c}\) nha.)
\(\left(2y+\dfrac{7}{2}\right)\cdot\dfrac{8}{3}=\dfrac{16}{3}\)
\(\Leftrightarrow2y=2-\dfrac{7}{2}=-\dfrac{3}{2}\)
hay \(y=-\dfrac{3}{4}\)