\(2xy-y=4x+3\)
\(\Rightarrow2xy-y-4x-3=0\)
\(\Rightarrow2xy-y-4x+2-5=0\)
\(\Rightarrow\left(2xy-4x\right)-\left(y-2\right)=5\)
\(\Rightarrow2x\left(y-2\right)-\left(y-2\right)=5\)
\(\Rightarrow\left(y-2\right)\left(2x-1\right)=5\)
Ta có bảng sau:
| 2x - 1 | 1 | 5 | -1 | -5 |
| y - 2 | 5 | 1 | -5 | -1 |
| x | 1 | 3 | 0 | -2 |
| y | 7 | 3 | -3 | 1 |
Vậy ...
#kễnh