Question

(2+x)(x2−2x+4)−(3+x2)×x=14          giúp mik vs

Answer 1

\(\Leftrightarrow x^3+8-x^3-3x=14\)

=>-3x=6

hay x=-2

Answer 2

`(2+x)(x^2-2x+4)-(3+x^2)x=14`

`<=>x^3+8-3x-x^3=14`

`<=>-3x=6`

`<=>x=-2`

Vậy `S={-2}`

Answer 3

\(\left(2+x\right)\left(x^2-2x+4\right)-\left(3+x^2\right)\cdot x=14\\ \Leftrightarrow x^3+8-x^3-3x=14\\ \Leftrightarrow\left(x^3-x^3\right)-3x+8=14\\ \Leftrightarrow-3x+8=14\\ \Leftrightarrow-3x=6\\ \Leftrightarrow x=-2\)

Answer 4

$\iff {}^{}+8-{}^{}-3x=14$

=>-3x=6

hay x=-2

Answer 5

$(2+x)({}^{}-2x+4)-(3+{}^{})x=14$

$\iff {}^{}+8-3x-{}^{}=14$

$\iff -3x=6$

$\iff x=-2$

Vậy $S=\{-2\}$

Answer 6

(2+x)(x2−2x+4)−(3+x2)⋅x=14⇔x3+8−x3−3x=14⇔(x3−x3)−3x+8=14⇔−3x+8=14⇔−3x=6⇔x=−2