Ta có: \(2x\left(x+2\right)^2-8x^2=2\left(x-2\right)\left(x^2+2x+4\right)\)
\(\Leftrightarrow2x\left(x^2+4x+4\right)-8x^2=2\left(x^3-8\right)\)
\(\Leftrightarrow2x^3+8x^2+8x-8x^2=2x^3-16\)
\(\Leftrightarrow2x^3+8x-2x^3+16=0\)
\(\Leftrightarrow8x+16=0\)
\(\Leftrightarrow8x=-16\)
hay x=-2
Vậy: S={-2}
1.giải phương trình :
1)1 + 2/x-1 + 1/x+3=x^2+2x-7/x^2+2x-3
2)x/x^2+5x+6=2/x^2+3x+2 (x=3)
3)1/x^2+9x+20 - 1/x^2+8x+12=x^2-2x-33/x^2+8x+15 (x=-5,7)
4)x+5/3x-6 - 1/2=2x-3/2x-4 (x=25/7)
5)x-1/x^3+1 + 2x+3/x^2-x+1=2x+4/x+1 - 2(x=0)
2x(x+2)x^2-8x^2=2(x-2)(x^2+2x+4)
Giải phương trình sau :
a) 11 + 8x – 3 = 5x – 3 + x
b) 2x(x + 2)² - 8x² = 2(x – 2)(x² + 2x + 4)
c) (x + 1)(2x – 3) = (2x – 1)(x + 5)
d) 0,1 – 2(0,5t – 0,1) = 2(t – 2,5) – 0,7
tìm x:
a.(x-3)^4-(x+3)^4+24x^3=216
b.(2x+1)(16x^4-8x^3+4x^2-2x+1)-(2x-1)(16x^4+8x^3+4x^2+2x+1)=2
tìm GTNN của bt:
x^2+2x+4
x^2-x-5/3/4
4x^2-x-3/16
2x(x+2)^2-8x^2=2(x-2)(x^2+2x+4)
2x(x+2)^2-8x^2=2(x-2)(x^2+2x+4)
2x(x+2)^2-8X^2=2(X-2)(X^2+2X+4)
2x(x+2)^2-8x^2=2(x-2)(x^2+2x+4)
Giải phương trình
1)(x-2)(x-1)=x(2x+1)+2
2)(x+2)(x+2)-(x-2)(x-2)=8x
3)(2x-1)(x^3-x+1)=2x^3-3x^2+16=0
4)(8x-3)(3x+2)-(4x+7)(x+4)=(2x+1)(5x-1)
5)(8-5x)(x+2)+4(x-2)(x+1)+2(x-2)(x+2)=0
6)4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
