2.x.(x-1,7)=0
\(\Rightarrow x.\left(x-1,7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x-1,7=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=1,7\end{cases}}\)
Vậy \(\orbr{\begin{cases}x=0\\x=1,7\end{cases}}\)k nhanguyễn đức tín
2.x.(x-1,7)=0
\(\Rightarrow x.\left(x-1,7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x-1,7=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=1,7\end{cases}}\)
Vậy \(\orbr{\begin{cases}x=0\\x=1,7\end{cases}}\)k nhanguyễn đức tín
\(Bài\) \(2:\) \(Tìm\) \(x:\)
b) \(\left(5-x\right)^3+27=0\)
d) \(\left(x^2-1\right).\left(x+7\right)=0\)
f) \(\left(x^2+81\right).\left(x-7\right).\left(x^2-2\right)=0\)
tìm x : a, x-2/5).(x+2/7)>0 b,(2x-1/2).(3x-1/3)<0
A= (-1/3)^-1 - (-6/7)^0 + (1/2)^2 :2
B= [(0,1)^2]^0 + [(1/7)^-1]^2 x 1/49 x [(2^2)^3 : 2^5]
Tìm x :
a , ( x -2 ) ( x + 7 ) bé hơn bằng 0.
b , ( x - 3 ) ( x - 4 ) bé hơn bằng 0 .
c , ( 3x + 1 ) ( x - 4 ) < 0.
d , ( x - 1 ) ( 2x - 1 ) > 0
a) (- 7) . ( 5 – x) < 0
b) 11 ⁝ x – 1
c) x + 8 ⁝ x + 1
d) (x + 2) . (5 – x) > 0
Tìm x:
a) x-7/2 <0
b)x.(x-2)>0
c)(x-3/5).(x+2/7)>0
d)5x-1/2 / 1,25-3x >0
a) 5/2 - x + 4/5 = 2/3 + 4/7
b) ( x - 1 ) x ( x + 2 )< 0
c) ( x + 3/5 ) x ( x+ 1 )<0
d) ( x - 1/3 ) x ( x + 2/5 )>0
Bài 1: Tìm x biết
1) |5x - 3| = |7 - x|
2) 2 |3 x - 1| - 3x = 7
3) |2x + 3| + 4 = -2x
4) |x + 3/4| - 1/3 = 0
5) 1,6 - |x + 1,5| = 0
6) |x - 1,5| + |2,5 - x| = 0
a) |3⋅x−1|=|5−2⋅x||3⋅x−1|=|5−2⋅x|
b) |x+2|−|x+7|=0|x+2|−|x+7|=0
c) |2⋅x−1|+x=2|2⋅x−1|+x=2
d) |x+1|+|2⋅y−1|=0|x+1|+|2⋅y−1|=0
giúp mk nha 4h đi học rùi mk
tick cho
Tìm x biết:
1) x (x-2016) + 2015 (2016-x) = 0
2) -5x (x-15) + (15-x) = 0
3) 3x (3x-7) - (7-3x) =0