Question

(2x+6)(4^x-64)=0

 

 

Answer 1

(2\(x+6\)).(4\(^x\) - 64) = 0

\(\left[{}\begin{matrix}2x+6=0\\4^x-64=0\end{matrix}\right.\)

\(\left[{}\begin{matrix}2x=6\\4^x=64\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=\dfrac{6}{3}\\4^x=4^3\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=2\\x=3\end{matrix}\right.\)

Vậy \(x\in\) {2; 3}

Answer 2

\(\left(2x+6\right)\left(4^x-64\right)=0\)

\(2x+6=0\) hoặc \(4^x-64=0\)

*) \(2x+6=0\)

\(2x=0-6\)

\(2x=-6\)

\(x=-6:2\)

\(x=-3\)

*) \(4^x-64=0\)

\(4^x=0+64\)

\(4^x=64\)

\(4^x=4^3\)

\(x=3\)

Vậy \(x=-3;x=3\)