\(\left(\dfrac{2x}{5}-1\right):\left(-5\right)=\dfrac{1}{7}\\ \Rightarrow\dfrac{2x}{5}-1=\dfrac{-5}{7}\\ \Rightarrow\dfrac{2x}{5}=\dfrac{2}{7}\\ \Rightarrow\dfrac{x}{5}=\dfrac{1}{7}\\ \Rightarrow x=\dfrac{5}{7}\)
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
tính C=1/3*5+1/5*7+1/7*9+............+1/(2X+1)(2X+3)=15/93
a,2/5+3/7+-3/5
b,1-5/7:x=-1/3
c,4/5*(x-1/3)=15/8
d,2/3:(2x+1/8)=7/3
e,2x+3/4=10/3-5/4
giúp mình với
tìm x biết1\3*5+1\5*7+1\7*9+....+1\(2x+1)(2x+3)
Tìm x
a. 2x + ( 1 - 5 )^2 = 7
b. | 1/2x + 1 | + 5 = 1/2
c. | 3x + 1/2 | - 1/3 = 1/3
d. | 2x - 3 | = 7/5
1/3 x 5 + 1/5 x 7 + 1/7 x 9+ ... + 1/(2x + 1) x (2x + 3) = 15/93.tinh x
1/3×5 +1/5×7 +.......+1/2x+1×2x+3=15/93
bài 3
d) \(\left(\frac{4}{5}\right)^{2x+7}=\frac{625}{256}\)
e) \(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+2}}{131}\)
Tìm x biết
\(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
