Question

(2x+3)×(x2+x)−2x(x2+2,5x)=9        giúp mik vs

Answer 1

\(\Leftrightarrow2x^3+2x^2+3x^2+3x-2x^3-5x^2=9\)

=>3x=9

hay x=3

Answer 2

\(\left(2x+3\right).\left(x^2+x\right)-2x\left(x^2+2,5x\right)=9\\ \Leftrightarrow2x^3+2x^2+3x^2+3x-2x^3-5x^2=9\\ \Leftrightarrow3x=9\\ \Leftrightarrow x=3\)

Answer 3

\(\left(2x+3\right).\left(x^2+x\right)-2x\left(x^2+2,5x\right)=9\)

\(\Leftrightarrow2x^3+2x^2+3x^2+3x-2x\left(x^2+2,5x\right)=9\)

\(\Leftrightarrow2x^3+2x^2+3x^2+3x-2x^3-5x^2=9\)

\(\Leftrightarrow2x^2+3x^2+3x-5x^2=9\)

\(\Leftrightarrow0+3x=9\)

\(\Leftrightarrow3x=9\)

\(\Leftrightarrow x=9:3\)

\(\Leftrightarrow x=3\)

Answer 4

$\iff 2{}^{}+2{}^{}+3{}^{}+3x-2{}^{}-5{}^{}=9$

=>3x=9

hay x=3

Answer 5

Answer 6

(2x+3).(x2+x)−2x(x2+2,5x)=9⇔2x3+2x2+3x2+3x−2x3−5x2=9⇔3x=9⇔x=3

 

Answer 7

$\left(2x+3\right).\left({}^{}+x\right)-2x\left({}^{}+2,5x\right)=9$

$\iff 2{}^{}+2{}^{}+3{}^{}+3x-2x\left({}^{}+2,5x\right)=9$

$\iff 2{}^{}+2{}^{}+3{}^{}+3x-2{}^{}-5{}^{}=9$

$\iff 2{}^{}+3{}^{}+3x-5{}^{}=9$