\(\left(2x+3\right)^2-\left(2x+1\right)\left(2x-1\right)=22\)
\(\left(4x^2+12x+9\right)-\left(4x^2-1^2\right)=22\)
\(4x^2+12x+9-4x^2+1=22\)
\(12x+10=22\)
\(12x=12\)
\(x=1\)
(2x+3)2 - (2x+1).(2x-1)=22
\(4x^2+12x+9-4x^2-1=22\)
\(12x+8 =22\)
\(12x=14\)
\(x=7/6\)
(2x + 3)2 - (2x + 1)(2x - 1) = 22
<=> 4x2 + 12x + 9 - 4x2 + 1 = 22
<=> 4x2 - 4x2 + 12x = 22 - 9 - 1
<=> 12x = 12
<=> x = 1
\(\left(2x+3\right)^2-\left(2x+1\right)\left(2x-1\right)=22\)
\(\Leftrightarrow4x^2+12x+9-4x^2+1=22\)
\(\Leftrightarrow12x=12\)
hay x=1
