TH1: 2x+1=5 <=> 2x=4 <=> x=2
TH2: 2x+1=-5 <=> 2x=-6 <=> x=-3
x thuộc {2 ; -3}
có 2 trường hợp:
TH1: 2x+1=5
=>2x=5-1=4
=>x=4:2=2
TH2: 2x+1=-5
=>2x=-5-1=-6
=>x=-6:2=-3
Vậy x= 2 ; -5
TH1: 2x+1=5 <=> 2x=4 <=> x=2
TH2: 2x+1=-5 <=> 2x=-6 <=> x=-3
x thuộc {2 ; -3}
có 2 trường hợp:
TH1: 2x+1=5
=>2x=5-1=4
=>x=4:2=2
TH2: 2x+1=-5
=>2x=-5-1=-6
=>x=-6:2=-3
Vậy x= 2 ; -5
giải phương trình:
a,\(\frac{155x-24}{51}+\frac{185x-48}{57}+\frac{205x-3}{61}\)=16
b, \(\frac{2019-x}{9}+\frac{19-x}{2000}+\frac{2009-x}{10}+\frac{4x}{2019}\)=1
Ai làm đúng mình tick cho, CẦN GẤPPPPP!!!!!!!!
a) Cho a+b+c=2 , ab+bc+ac=1 .CMR: 0<=a,b,c<=4/3
b) Cho x,y,z, >0 sao cho x+y+z<=1.CMR: x+y+z+ 1/x +1/y + 1/z >= 10 . . . CÁC BẠN GIÚP MÌNH NHÉ MÌNH ĐANG CẦN GẤPPPPP!!!!!!!
Giúp mình nhé.
1/ (x-3). (2x-5) -3x. (x+4)
2/ (1/2x+5). (2x- 1/5)
3/ (x2-3x+5). (2x-5)
d) (3x – 5)(7 – 5x) – (5x + 2)(2 – 3x) = 4 g) 3(2x - 1)(3x - 1) - (2x - 3)(9x - 1) =0 j) (2x – 1)(3x + 1) – (4 – 3x)(3 – 2x) = 3 k) (2x + 1)(x + 3) – (x – 5)(7 + 2x) = 8 m) 2(3x – 1)(2x + 5) – 6(2x – 1)(x + 2) = - 6
Giải phương trình
1) 2x ( x – 3 ) + 5 ( x – 3 ) = 0
2) ( x2 – 4 ) – ( x – 2 ) ( 3 – 2x ) = 0
3) ( 2x – 1 )2 – ( 2x + 5 )2 = 11
4) ( 2x + 1 )2 ( 3x – 5 ) = 4x2 – 1
5) 3x2 – 5x – 8 = 0
6) ( 2x + 1 )2 ( 3x – 5 ) = 4x2 – 1
7) 3x2 – 5x – 8 = 0
8) \(\left|x-5\right|=3\)
9) \(\left|2x-5\right|=3-x\)
10) \(\left|2x+1\right|=\left|x-1\right|\)
11) \(\dfrac{5x+2}{6}-\dfrac{8x-1}{3}=\dfrac{4x+2}{5}-5\)
12) \(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=2x+\dfrac{5}{3}\)
. Tìm x, biết:
a) 6x.(x – 5) + 3x.(7 – 2x) = 18 b) 2x.(3x + 1) + (4 – 2x).3x = 7 c) 0,5x.(0,4 – 4x) + (2x + 5).x = -6,5 | d) (x + 3)(x + 2) – (x - 2)(x + 5) = 6 e) 3(2x - 1)(3x - 1) – (2x - 3)(9x - 1) = 0 |
2x^2 + 3x –5 = 0
2x(3x – 5) – 5 + 3x = 0
(2x – 1)^2 – (2x + 5)(2x – 5) = 18
tìm x giúp tui với
Tìm x:
1, 2(x-3)2-(5-2x)2=3-2x2
2,1/2 (2x+1)2 - 1/2 ( 2x-1)2=0
3, (2x+5) (2x-5) -( 2x-5)2=0
tìm x
1) (3x-2)(9x^2+6x+4)-(2x-5)(2x+5)=(3x-1)^3-(2x+3)^2+9x(3x-1)
2) (2x+1)^3-(3x+2)^2=(2x-5)(4x^2+10x+25)+6x(2x+1)-9x^2