2x + 1 = (2x + 1)²
(2x + 1)² - (2x + 1) = 0
(2x + 1)(2x + 1 - 1) = 0
2x(2x + 1) = 0
2x = 0 hoặc 2x + 1 = 0
*) 2x = 0
x = 0
*) 2x + 1 = 0
2x = -1
x = -1/2
Vậy x = -1/2; x = 0
(2x+1)^2+(2x-1)^2-2(2x-1)(2x+1)
Tính (rút gọn )
1, 2x(3x-1)-(2x+1)(x-3)
2, 3(x^2-2x)-(4x+2)(x-1)
3, 3x(x-5)-(x-2)^2 -(2x+3)(2x-3)
4, (2x-3)^2+(2x-1) (x+4)
d) (3x – 5)(7 – 5x) – (5x + 2)(2 – 3x) = 4 g) 3(2x - 1)(3x - 1) - (2x - 3)(9x - 1) =0 j) (2x – 1)(3x + 1) – (4 – 3x)(3 – 2x) = 3 k) (2x + 1)(x + 3) – (x – 5)(7 + 2x) = 8 m) 2(3x – 1)(2x + 5) – 6(2x – 1)(x + 2) = - 6
(2x-3)^2+(2x-1)(2x+1)-(2x+1)(4x^2-2x+1)+8x^3(x-1)=13
Thực hiện phép tính
a, (2x+1)^2+(2x-1)^2-2(2x+1)(2x-1)
b,(2x^3-3x^2+6x-9)(2x-3)
1-2x/2x + 2x/2x-1 + 1/2x-4x^2
Phân thức đại số
a) 1-2x/2x + 2x/2x-1 + 1/2x-4x^2
b) x^2 + 1 - x^4+1/x^2+1
c) 3x+2/x^2-2x+1 - 6/x^2-1 - 3x-2/x^2+2x+1
d) a^2-b^2/a^2 * a^4/(a+b)^2
giải phương trình sau
1/ ( x-1) (2x+1) =0
2/ x (2x-1) (3x+15) =0
3/ (2x-6) (3x+4) x=0
4/ (2x-10)(x^2+1)=0
5/ (x^2+3) (2x-1) =0
6/ (3x-1) (2x^2 +1)=0
\((2x^2+2x+1).\left(2x^2-2x+1\right)-\left(2x^2+1\right)^2\)
(2x-1/x)^4
(2x^2-1/x)^4
[(2x)^2-1/x]^4
[(2x)^2-1/x^2]^4
