9=32
(2x+1)2=32
(2x+1) =3
2x =3-1
2x =2
x =1
k
9=32
(2x+1)2=32
2x+1 =3
2x =2
x = 1
h nha
Ta có:(2x+1)2=9
(2x+1)2=32=(-3)2
\(\Rightarrow\orbr{\begin{cases}2x+1=3\\2x+1=-3\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}2x=2\\2x-4\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=2\\x=-1\end{cases}}\)
Ta có:
\(\left(2x+1\right)^2=9\)
\(\Rightarrow\left(2x+1\right)^2=3^2\)
\(\Rightarrow2x+1=3\)
\(2x=3+1\)
\(2x=4\)
\(x=4:2\)
\(x=2\)
