Question

( 2x + \(\dfrac{3}{5}\) )² - \(\dfrac{9}{25}\) = 0

Answer 1

\(\left(2x+\dfrac{3}{5}\right)^2-\dfrac{9}{25}=0\)

=>\(\left(2x+\dfrac{3}{5}\right)^2=\dfrac{9}{25}\)

=>\(\left[{}\begin{matrix}2x+\dfrac{3}{5}=\dfrac{3}{5}\\2x+\dfrac{3}{5}=-\dfrac{3}{5}\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}2x=\dfrac{3}{5}-\dfrac{3}{5}=0\\2x=-\dfrac{3}{5}-\dfrac{3}{5}=-\dfrac{6}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{3}{5}\end{matrix}\right.\)