Question

(2x-3)(x²-4)=0

Answer 1

\(\left(2x-3\right)\left(x^2-4\right)=0\)

\(\Leftrightarrow\left(2x-3\right)\left(x-2\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-3=0\\x-2=0\\x+2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}2x=3\\x=2\\x=-2\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=2\\x=-2\end{matrix}\right.\)

Answer 2

\(\Leftrightarrow\) \([|^{x^2-4=0}_{2x-3=0}\)  

\(\Leftrightarrow\)\(\left[{}\begin{matrix}x=2\\x=-2\\x=\dfrac{3}{2}\end{matrix}\right.\)

Answer 3

`(2x-3)(x^2-4)=0`

`<=>(2x-3)(x-2)(x+2)=0`

<=>\(\left[{}\begin{matrix}2x-3=0\\x-2=0\\x+2=0\end{matrix}\right.\)

<=>\(\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=2\\x=-2\end{matrix}\right.\)

Vậy phương trình đã cho có nghiệm là x=`3/2`; x=`2` hoặc x=`-2`