Question

 (2x-3)^2 -3(x-3)=4x

Answer 1

\(\left(2x-3\right)^2-3\left(x-3\right)=4x\\ \Leftrightarrow4x^2-12x+9-3x+9-4x=0\\ \Leftrightarrow4x^2-19x+18=0\)

\(\Delta=\left(-19\right)^2-4.4.18=361-288=73\)

\(x_1=\dfrac{-\left(-19\right)+\sqrt{73}}{2.4}=\dfrac{19+\sqrt{73}}{8}\)

\(x_2=\dfrac{-\left(-19\right)-\sqrt{73}}{2.4}=\dfrac{19-\sqrt{73}}{8}\)

Answer 2

\(4x^2-12x+9-3x+9=4x\Leftrightarrow4x^2-19x+18=0\)

\(\Delta=19^2-4.4.18=73>0\)

Vậy pt có 2 nghiệm pb 

\(x=\dfrac{19\pm\sqrt{73}}{8}\)