Các câu hỏi tương tự
1+1/2 x (1+2) + 1/3 x (1+2+3) + ...........+ 1/16 x (1+2+3+......16) = ?
1. ( x + 1/2 )^2 = 1/16
2.( x-1/2)^2=16
a,1/2(x-4)-1/4(x-4/3)=2(x-1/2)
b, 3/4-(x-1/2)^2=-11/2
c,3/16+1/1/16.(x-2/3)^2=3/4
Ta có: 4x=5y => x/5=y/4=>x2/25=y2/16
ta có:
x2/25=y2/16=x2-y2/25-16=1/9
x^2/25=1/9=>x^2=25/9=>x=5/3
y^2/16=1/9=>y^2=16/9=>y=4/3
tích của chúng bằng:5/3*4/3=20/9
Tìm x biết
( x + 1/2 )^2 -1/16 =0
( 3x + 1/2 )^2 + 25/16 = 0
\(\frac{1}{1-x}+\frac{1}{1+x}+\frac{2}{1+x^2}+\frac{4}{1+x^4}+\frac{8}{1+x^8}+\frac{16}{1+x^{16}}\)
tìm x biết (1/1*101+1/2*102+...+1/16*116)*x=1/1*11+1/2*12+...+1/16*26
Tim cac gia tri x, y thoa man:
a, ( x2 - 1 ) ( x2 - 16 ) < 0 ca x thuoc z
b, 1/x - y/8 = 1/16 va x, y thuoc N
c, | x+1 | + | x+2 | + | x+3 | = x
tim cac gia tri x y thoa man
a,(x^2-1)(x^2-16)<0 va x thuoc Z
B,1/x-y/8=1/16 va x y thuoc N
\(2^{x-1}=16\)
|x+3|=7
\(\dfrac{1}{5}+x=\dfrac{1}{2}\)