\(2 ( x − 1 ) − 5 ( x + 2 ) = 10\)
\(⇔ 2 x − 2 − 5 x − 10 = 10\)
\(⇔ 2 x − 5 x = 10 + 10 + 2\)
\(⇔ − 3 x = 22\)
`<=>x=-22/3`
`2(x-1)-5(x+2)=10`
`=>2x-2-5x-10=10`
`=>-3x-12=10`
`=>-3x=10+12`
`=>-3x=22`
`=>x=22:(-3)~`
`=>x=-22/3`
Vậy `x=-22/3`
\(2\left(x-1\right)-5\left(x+2\right)=10\)
\(\Leftrightarrow2x-2-5x-10=10\)
\(\Leftrightarrow-3x-12-10=0\)
\(\Leftrightarrow-3x-22=0\)
\(\Leftrightarrow x=\dfrac{22}{3}\)
Vậy \(S=\left\{\dfrac{22}{3}\right\}\)