\(\left(2n-3\right)^3=1\)
\(\left(2n-3\right)^3=1^3\)
\(2n-3=1\)
\(2n=4\)
\(n=2\)
(2n - 3)3 = 1
(2n - 3)3 = 13
2n - 3 = 1
2n = 4
n =\(\dfrac{4}{2}\)
n = 2
\(\left(2n-3\right)^3=1\)
\(\Leftrightarrow2n-3=1\)
\(\Leftrightarrow2n=4\)
\(\Leftrightarrow n=2\)
Vậy n = 2.
(2n-3)3=1=13
=>2n-3=1
=>2n=3+1=4
=>n=4/2=2
(2n - 3)3 = 1
(2n - 3)3 = 13
2n - 3 = 1
2n = 4
n = 2
