\(=1-\dfrac{\sqrt{2}}{\sqrt{3}}+\dfrac{2}{3}\sqrt{2}\)
( căn 12 - căn 27 - 3 căn 2 ) . 2 căn 3 + 6 căn 6
tính
a) \(\left(\dfrac{2\sqrt{3}-\sqrt{6}}{\sqrt{8}-\sqrt{2}}+1\right)\dfrac{1}{2+\sqrt{6}}\)
b) \(\sqrt{27}-6\sqrt{\dfrac{1}{3}}+\dfrac{\sqrt{3}-3}{\sqrt{3}}\)
a)5\(\sqrt{27}\)+3\(\sqrt{48}\)-2\(\sqrt{12}\)-6\(\sqrt{3}\)
b)\(\dfrac{3}{2+\sqrt{3}}\)+\(\dfrac{13}{4-\sqrt{3}}\)+\(\dfrac{6}{\sqrt{3}}\)
Câu 1: Thực hiện phép tính:
a. \(\sqrt{3}\left(2\sqrt{6}-\sqrt{3}\right)-6\sqrt{2}\)
b. \(6\sqrt{12}-\sqrt{20}-2\sqrt{27}+\sqrt{125}\)
c. \(\sqrt{\left(1-\sqrt{3}\right)^2}-3\sqrt{\dfrac{1}{3}}\)
d. \(\dfrac{6}{\sqrt{6}}-\dfrac{5}{\sqrt{6}-1}\)
\(c,2\sqrt{\dfrac{16}{3}}-3\sqrt{\dfrac{1}{27}}-6\sqrt{\dfrac{4}{75}}\)
d,\(\sqrt{\dfrac{2-\sqrt{3}}{2+\sqrt{3}}}+\sqrt{\dfrac{2+\sqrt{3}}{2-\sqrt{3}}}\)
Bài 1. Tính
\(G=\sqrt[3]{2+10\sqrt{\frac{1}{27}}}+\sqrt[3]{2-10\sqrt{\frac{1}{27}}}\)
\(H=\sqrt[3]{1+\sqrt{2}}.\sqrt[6]{3-2\sqrt{2}}\)
\(\dfrac{\sqrt{6}+\sqrt{14}}{2\sqrt{3}+\sqrt{28}}\)
\(\dfrac{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+4}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\)
\(\dfrac{3\sqrt{8}-2\sqrt{12}+\sqrt{20}}{3\sqrt{18}-2\sqrt{27}+\sqrt{45}}\)
\(\left(\sqrt{27}-3\sqrt{2}+2\sqrt{6}\right):3\sqrt{3}\)
1) Tính:
\(b,\sqrt{2}.\sqrt{7+3\sqrt{5}}-\dfrac{4}{\sqrt{5-1}}\)
\(c,\sqrt{27}-6\sqrt{\dfrac{1}{3}}+\dfrac{\sqrt{3}-3}{\sqrt{3}}\)
\(d,\dfrac{9-2\sqrt{3}}{3\sqrt{6}-2\sqrt{2}}\)
Giúp mình với, mình cần gấp
\(\frac{\left(\sqrt{27}-3\sqrt{2}+2\sqrt{6}\right)}{3\sqrt{3}}\)
