Question

25-{x+[x+(-8)]}=0

Answer 1

25−(𝑥+[𝑥+(−8)])=0

⇔25−(𝑥+[𝑥−8])=0

⇔25−(𝑥+𝑥−8)=0

⇔25−(2𝑥−8)=0

⇔25−2𝑥+8=0

⇔33−2𝑥=0

⇔−2𝑥+33=0

⇔𝑥=\(\dfrac{33}{2}\)

 

 

Answer 2

25−(𝑥+[𝑥+(−8)])=0

⇔25−(𝑥+[𝑥−8])=0

⇔25−(𝑥+𝑥−8)=0

⇔25−(2𝑥−8)=0

⇔25−2𝑥+8=0

⇔33−2𝑥=0

⇔−2𝑥+33=0

⇔𝑥=