\(\dfrac{2}{3}x\dfrac{1}{2}+\dfrac{1}{3}\)
\(\dfrac{2}{3}\cdot\dfrac{1}{2}=\dfrac{2}{6}\)
\(\dfrac{2}{6}+\dfrac{1}{3}=\dfrac{2}{6}+\dfrac{2}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
\(\dfrac{2}{3}\cdot\dfrac{1}{2}+\dfrac{1}{3}=\dfrac{1}{3}+\dfrac{1}{3}=\dfrac{2}{3}\)