\(=\dfrac{2017}{3}+\dfrac{2017}{6}+...+\dfrac{2017}{2031120}\)
\(=2017\left(\dfrac{1}{3}+\dfrac{1}{6}+...+\dfrac{1}{2031120}\right)\)
\(=2007\cdot2\cdot\left(\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{2016\cdot2015}\right)\)
\(=4014\cdot\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2015}-\dfrac{1}{2016}\right)\)
\(=4014\cdot\dfrac{1007}{2016}=\dfrac{224561}{112}\)
cho A =1+2^2018+3^2017+4^2016+...+2018^2+2019,B=1+2^2017+3^2016+...+2017^2+2018,chứng tỏ giá trị biểu thức A-3B dương
1+2018+2*2017+3*2016+..........................+2016*3+2017+2+2018*1
1+(1+2)+(1+2+3)+..........................(1+2+3+...............+2017+2018
2017/1+2 + 2017/1+2+3 + 2017/1+2+3+4 + ..... + 2017/1+2+3+....+2016
ai làm nhanh nhất mình tích cho
Find K such that: K-2006=1+(1+2+3)+ ...(1+...+2007) / 2017*1+2016*2+2015*3+...+2*2016+1*2017
Tìm K sao cho: \(K-2016=\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+2017\right)}{2017\times1+2016\times2+2015\times3+...+2\times2016+2017\times1}\)
tính tổng sau 1/1*2 + 1/2*3 + 1/3*4 + ... + 1/2016*2017 +1
Find K such that : K - 2016 = 1 + ( 1 + 2 ) + ( 1 + 2 + 3 ) + ... + ( 1 + 2 + 3 + ... + 2017 ) / 2017 x 1 + 2016 x 2 + 2015 x 3 + ... + 2 x 2016 + 1 x 2017
Answer : K = ........
AI GIẢI TRƯỚC CHO MIK ĐẦU TIÊN THÌ MIK CLICK CHO, HỨA LUN^^
GIÚP CHO MIK VS NHÉ
NẾU BIK LỜI GIẢI THÌ GHI RA LUÔN, HOK BIK THÌ CHỈ CẦN GHI ĐÁP ÁN LÀ ĐC
So sánh 1/2*3+1/3*4+1/4*5+........+1/2016*2017 với 1/2
Find K such that:
K - 2016 = \(\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+2017\right)}{2017\times1+2016\times2+2015\times3+...+2\times2016+1\times2017}\)
M=3/1×2+3/2×3+3/3×4+...........+3/2015×2016+3/2016×2017
Giúp mk nhanh nha 😀
