Question

2, phân tích đa thức thành nhân tử  

a, x^2-3x+2                                      b , x^2+x-6

c, 3x^2-8x+4                                     d, 4x^2-4x-3

Answer 1

\(x^2-3x+2=x^2-x-2x+2=x\left(x-1\right)-2\left(x-1\right)=\left(x-1\right)\left(x-2\right)\)

\(x^2+x-6=x^2-2x+3x-6=x\left(x-2\right)+3\left(x-2\right)=\left(x-2\right)\left(x+3\right)\)

\(3x^2-8x+4=3x^2-6x-2x+4=3x\left(x-2\right)-2\left(x-2\right)=\left(x-2\right)\left(3x-2\right)\)

\(4x^2-4x-3=4x^2+2x-6x-3=2x\left(2x+1\right)-3\left(2x+1\right)=\left(2x-3\right)\left(2x+1\right)\)

Answer 2

a: =(x-1)(x-2)

b: =(x+3)(x-2)

c: \(=3x^2-2x-6x+4=\left(3x-2\right)\left(x-2\right)\)

d: \(=4x^2-6x+2x-3=\left(2x-3\right)\left(2x+1\right)\)