\(=1+\frac{1}{1.3}+\frac{1}{3.2}+\frac{1}{2.5}+\frac{1}{5.3}+\frac{1}{3.7}+\frac{1}{7.4}+\frac{1}{4.9}+\frac{1}{9.5}\)
\(=1+1-\frac{1}{5}\)
\(=\frac{10}{5}-\frac{1}{5}\)
\(=\frac{9}{5}\)
Ai thấy đúng thì
ồ, câu hỏi này hay đấy chứ
đặt A = \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}\)
A = \(\frac{2}{2.3}+\frac{2}{2.6}+\frac{2}{2.10}+\frac{2}{2.15}+\frac{2}{2.21}+\frac{2}{2.28}+\frac{2}{2.36}+\frac{2}{2.45}\)
A = \(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+\frac{2}{30}+\frac{2}{42}+\frac{2}{56}+\frac{2}{72}+\frac{2}{90}\)
A = \(\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+\frac{2}{5.6}+\frac{2}{6.7}+\frac{2}{7.8}+\frac{2}{8.9}+\frac{2}{9.10}\)
A = \(2.\left(\frac{1}{2}-\frac{1}{3}\right)+2.\left(\frac{1}{3}-\frac{1}{4}\right)+2.\left(\frac{1}{4}-\frac{1}{5}\right)+2.\left(\frac{1}{5}-\frac{1}{6}\right)+2.\left(\frac{1}{6}-\frac{1}{7}\right)+2.\left(\frac{1}{7}-\frac{1}{8}\right)+2.\left(\frac{1}{8}-\frac{1}{9}\right)+2.\left(\frac{1}{9}-\frac{1}{10}\right)\)A = \(2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\right)\)
A = \(2.\left(\frac{1}{2}-\frac{1}{10}\right)\)
A = \(2.\frac{2}{5}\)
A = \(\frac{4}{5}\)
\(\Rightarrow1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}=1+\frac{4}{5}=\frac{9}{5}\)