\(1,\dfrac{1}{3}:\left|2x+1\right|=\dfrac{6}{7}-\left(-\dfrac{1}{7}\right)\\ \left|2x+1\right|=\dfrac{1}{3}:1\\ \left|2x+1\right|=3\\ 2x+1=3\\ 2x=2\\ x=1\\ 2,\left|0,3-x\right|:-\dfrac{1}{4}=-2,5\\ \left|0,3-x\right|=\dfrac{5}{8}\\ 0,3-x=\dfrac{5}{8}\\ x=0,3-\dfrac{5}{8}\\ x=-\dfrac{13}{40}\)