1.cho A=3/4+8/9+15/16+...+2499/2500
CMR:48<A<49
2.Tìm GTNN của biểu thức sau: E=3x4+ |5y-1| + |5y-2|
Cmr 3/4 + 8/9 + 15/16 + ... + 2499/2500 > 48
CMR M=3/4+8/9+15/16+..+2499/2500>48
Cho c=3/4+8/9+15/16+...+2499/2500
CMR C lớn hơn 48 biết C có 49 số hạng
\(CMR:\frac{3}{4}+\frac{8}{9}+\frac{15}{16}+.....+\frac{2499}{2500}>48\left(49>A>48\right)\)
Chứng minh rằng A=\(\dfrac{3}{4}+\dfrac{8}{9}+\dfrac{15}{16}+...+\dfrac{2499}{2500}>48\)
CMR :a) \(\frac{1}{2^2}+\frac{1}{4^2}+\frac{1}{6^2}+.....+\frac{1}{100^2}< \frac{1}{2}\)
b) \(\frac{3}{4}+\frac{8}{9}+\frac{15}{16}+....+\frac{2499}{2500}>48\)
Cho C = 2 + 3/4 + 8/9 + 15/16 + ... + 2499/2500
CMR C > 50