\(=\dfrac{1}{99\cdot97}-\dfrac{1}{2}\left(\dfrac{2}{1\cdot3}+\dfrac{2}{3\cdot5}+...+\dfrac{2}{95\cdot97}\right)\)
\(=\dfrac{1}{99\cdot97}-\dfrac{1}{2}\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{95}-\dfrac{1}{97}\right)\)
\(=\dfrac{1}{99\cdot97}-\dfrac{1}{2}\cdot\dfrac{96}{97}=\dfrac{-4751}{9603}\)
1/99-1/99.97-1/97.95-1/95.93-...+1/5.3-1/3.1
1/99.97-1/97.95-1/95.93-...-1/5.3-1/3.1 = ?
1/99.97-1/97.95-1/95.93...-1/5.3-1/3.1
1/99.97 - 1/97.95 - 1/95.93 - ... - 1/5.3 - 1/3.1. Thực hiện phép tính
Tính: \(B=\dfrac{1}{99.97}-\dfrac{1}{97.95}-\dfrac{1}{95.93}-...-\dfrac{1}{5.3}-\dfrac{1}{3.1}\)
\(\frac{1}{99.97}-\frac{1}{97.95}-\frac{1}{95.93}-\frac{1}{5.3}-\frac{1}{3.1}=.....\)
\(\frac{1}{99.97}-\frac{1}{97.95}-\frac{1}{95.93}-...-\frac{1}{5.3}-\frac{1}{3.1}\)
Thực hiện phép tính:
1/99.97 - 1/97.95 - 1/95.93 - .........- 1/5.3 - 1/3.1
A=\(\frac{1}{99.97}-\frac{1}{97.95}-\frac{1}{95.93}-....-\frac{1}{5.3}-\frac{1}{3.1}\)
