Question

(195-(3.x-27)].39=4212

Answer 1

\(\left[195-\left(3x-27\right)\right]\cdot39=4212\\ \Rightarrow195-\left(3x-27\right)=4212:39\\ \Rightarrow195-\left(3x-27\right)=108\\ \Rightarrow3x-27=195-108\\ \Rightarrow3x-27=87\\ \Rightarrow3x=87+27\\ \Rightarrow3x=114\\ \Rightarrow x=114:3\\ \Rightarrow x=38\)

Answer 2

\(\left[195-\left(3x-27\right)\right]\cdot39=4212\\ \Leftrightarrow195-\left(3x-27\right)=108\\ \Leftrightarrow3x-27=87\\ \Leftrightarrow3x=114\\ \Leftrightarrow x=38\)

Vậy x = 38.

Answer 3

[195−(3x−27)]⋅39=4212

⇒195−(3x−27)=4212:39

⇒195−(3x−27)=108

⇒3x−27=195−108

⇒3x−27=87⇒3x=87+27✿

⇒3x=114⇒x=114:3⇒x=38