18x-6+2x(x-1)=0
=>x(x-1)+9x-3=0
=>\(x^2-x+9x-3=0\)
=>\(x^2+8x-3=0\)
=>\(x^2+8x+16=19\)
=>\(\left(x+4\right)^2=19\)
=>\(\left[\begin{array}{l}x+4=\sqrt{19}\\ x+4=-\sqrt{19}\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\sqrt{19}-4\\ x=-\sqrt{19}-4\end{array}\right.\)
a, 2x²-18x+28=0. b, x-2/x²-9+3x-1/x+3=2x+1/x-3+1
Tìm x
a) (x + 3)2 + (x + 2)(5 – x) = 1
b/ (2x – 1)2 – ( x – 5)( 4x + 3) = 3
c/ 3x (x – 2) + 4x – 8 = 0
d/ 2x (3x + 5) – 18x – 30 = 0
Tìm x:
a) x3-6x2+12x-8=\(\dfrac{-1}{1000}\)
b) x3-81x=0
c)x(7-2x)-7+2x=0
d)(9x2-x)-18x+2=0
( 2x^2 + 3x -1 )^2 -( x^2 -x +1)^2
(x^2 +5x ).(x^3 +3x^2 -18x) =0
x^2 - 4x + 5 = 0
2x^2 + 20x + 52
a)Thực hiện phép tính:(3x+1)(3x-1)-(18x^3+5x^2-2x):2x
b)Tìm x biết:3x(x-2021)-x+2021=0
a) (2x-1)2-(x+3)=0
b) 2x3-12x2+18x=0
c) x3+5x2+4x+20=0
tính
(x+y-1)^2-2(x+y-1)(x+y)+(x+y)^2
tìm x
2x^3-18x=0
Tìm x:
A/ 5x²(3x-1)-10x³(1-3x) = 0
B/ 9x(x-3)+18x²(3-x) - 81x²(x-3) = 0
C/ (4x-1)(3x-5)-x(4x-1) = 3(1-4x)
D/ 2x²(3x+1)+7(3x+1) = 2x(3x+1)
(x2-2x) (x3-3x2-18x) = 0
