Question

(1/6+2 và 1/12-10,75).x-7=(2/5+3/8+0,25):0,1

Answer 1

\(\left(\dfrac{1}{6}+2\dfrac{1}{12}-10,75\right)\cdot x-7=\left(\dfrac{2}{5}+\dfrac{3}{8}+0,25\right):0,1\)

=>\(\left(\dfrac{1}{6}+\dfrac{25}{12}-\dfrac{43}{4}\right)\cdot x-7=\left(\dfrac{2}{5}+\dfrac{3}{8}+\dfrac{1}{4}\right)\cdot10\)

=>\(x\cdot\left(\dfrac{2}{12}+\dfrac{25}{12}-\dfrac{129}{12}\right)-7=\dfrac{16+15+10}{40}\cdot10\)

=>\(x\cdot\dfrac{-102}{12}-7=\dfrac{41}{4}\)

=>\(x\cdot\dfrac{-17}{2}=\dfrac{41}{4}+7=\dfrac{41+28}{4}=\dfrac{69}{4}\)

=>\(x=-\dfrac{69}{4}:\dfrac{17}{2}=-\dfrac{69}{4}\cdot\dfrac{2}{17}=\dfrac{-69}{34}\)