\(\left(\dfrac{1}{5x}\right)^2\left(5x^3-x-25\right)\)
= \(\dfrac{1}{25x^2}.\left(5x^3-x-25\right)\)
= \(\dfrac{x}{5}-\dfrac{1}{25x}-\dfrac{1}{x^2}\)
tìm x biết 25(x+3)^2+(1-5x)(1+5x)=0
Các bạn giúp mình nhé càng nhanh càng tốt nhà
(5x-1). (2x+3)-3. (3x-1)=0
x^3 (2x-3)-x^2 (4x^2-6x+2)=0
x (x-1)-x^2+2x=5
(3x+2)(x-1)-3 (5x+2)+5 (11-4x)=25
8 (x-2)-2 (3x-4)=25
(3x+4). (5x-1)+(5x+2). (1-3x)+2=0
(5x-1). (2x+7)-(2x-3). (5x+9)
4 (x-1). (X+5)-(x+5). (X+2)=3. (X-1)(x+2)
2x^2+3 (x-1). (X+1)=5x(x+1)
4. (18-5x)-12 (3x-7)=1825. (2x-16)-6 .(x+4)
1/2x. (2/5-4x)+(2x+5).x=-13/2
Nhiều các bạn giả đùm mình nha
Thanh nhiều
giải các phương trình sau
1, \(\dfrac{5x^2-12}{x^2-1}+\dfrac{3}{x-1}=\dfrac{5x}{x+1}\)
2, \(\dfrac{3}{x-5}-\dfrac{15-3x}{x^2-25}=\dfrac{3}{x+5}\)
3, \(\dfrac{-3}{x-4}-\dfrac{3-5x}{x^2-16}=\dfrac{1}{x+4}\)
BT3: Tìm x
\(a,\left(x+2\right)^2-9=0\)
\(b,x^2-2x+1=25\)
\(c,\left(5x+1\right)^2-\left(5x-3\right)\left(5x+3\right)=30\)
\(d,\left(x-1\right)\left(x^2+x+1\right)+x\left(x+2\right)\left(2-x\right)=5\)
Giải phương trình:
A/ 2×-5=-x+4. B/(4x-10)(25+5x)=0.
c/1+ x/3-x=5x/(x+2)(3-x)+2/x+2.
D/ x/3 -2x+1/2 =x/6-x
Giải phương trình:
e)4(x-3)2-(2x-1)(2x+1)=10
f) 25(x+3)2+(1-5x)(1+5x)=8
g)9(x+1)2-(3x-2)(3x+2)=10
h)-4(x-1)2+(2x-1)(2x+1)=-3
tìm x biết
a)x2-2x+1=25 b)(5x+1)2-(5x-3)(5x+3)=30
a, [(x/x^2-25) - (x-5/X^2+5x)] : (2x-5/x^2+5x) + ( x/ 5-x)
b, [(9/x^3-9x) + (1/x+3)] : [(x-3/x^2+ 3x) - ( x/3x+9)]
c, (1/x-1) - (x^3-x/x^2+1) . [(x/x^2+1-2x) + (1/1-x^2)]
(x + 2)^3 - (x - 5) . ( x^2 + 5x + 25) -6 . (x + 3)^2 = -2x + 1
