3/4 - (x - 2/3) = 1 1/3
3/4 - x + 2/3 = 4/3
-x = 4/3 - 3/4 - 2/3
-x = -1/12
x = 1/12
3/4 - (x - 2/3) = 1 1/3
3/4 - x + 2/3 = 4/3
-x = 4/3 - 3/4 - 2/3
-x = -1/12
x = 1/12
a) 2 bn làm gòi
b)|1/3-x|=2/5
TH1: 1/3-x=2/5
⇔x=1/3-2/5
⇔x=-1/15
TH2: 1/3-x=-2/5
⇔x=1/3+2/5
⇔x=11/15
Vậy x ϵ {-1/15;11/15}
b)(x-1)/3=27/(x-1)
⇔(x-1)2=3x27
⇔(x-1)2=81
TH1: x-1=9
⇔x=10
TH2:x-1=-9
⇔x=-8
Vậy x ϵ {-8;10}
EZ :>
a)3/4 - (x - 2/3) = 1 1/3
3/4 - x + 2/3 = 4/3
-x = 4/3 - 3/4 - 2/3
-x = -1/12
x = 1/12
b)|1/3-x|=2/5
TH1: 1/3-x=2/5
⇔x=1/3-2/5
⇔x=-1/15
TH2: 1/3-x=-2/5
⇔x=1/3+2/5
⇔x=11/15
Vậy x ϵ {-1/15;11/15}
c)
(x-1)/3=27/(x-1)
⇔(x-1)2=3x27
⇔(x-1)2=81
TH1: x-1=9
⇔x=10
TH2:x-1=-9
⇔x=-8
Vậy x ϵ {-8;10}
a)3/4 - (x - 2/3) = 1 1/3
3/4 - x + 2/3 = 4/3
-x = 4/3 - 3/4 - 2/3
-x = -1/12
x = 1/12
b)|1/3-x|=2/5
TH1: 1/3-x=2/5
⇔x=1/3-2/5
⇔x=-1/15
TH2: 1/3-x=-2/5
⇔x=1/3+2/5
⇔x=11/15
Vậy x ϵ {-1/15;11/15}
c)
(x-1)/3=27/(x-1)
⇔(x-1)2=3x27
⇔(x-1)2=81
TH1: x-1=9
⇔x=10
TH2:x-1=-9
⇔x=-8
Vậy x ϵ {-8;10}
a)3/4-(x-2/3)=4/3
(x-2/3)=3/4-4/3
x-2/3=-7/12
x=-7/12+2/3
x=1/12
b)[1/3-x]=2/5
Th1:1/3-x=-2/5
x=1/3--2/5
x=1/3+2/5
x=11/15
Th2:1/3-x=2/5
x=1/3-2/5
x=-1/15
c)x-1/3=27/x-1
(x-1)2=3.27
(x-1)2=81
Th1:
x-1=9
x=9+1
x=10
Th2:
x-1=-9
x=-9-1
x=-10
a) 3/4 - (x - 2/3) = 1 1/3
3/4 - x + 2/3 = 4/3
-x = 4/3 - 3/4 - 2/3
-x = -1/12
x = 1/12
b)|1/3-x|=2/5
TH1: 1/3-x=2/5
⇔x=1/3-2/5
⇔x=-1/15
TH2: 1/3-x=-2/5
⇔x=1/3+2/5
⇔x=11/15
Vậy x ϵ {-1/15;11/15}
c)(x-1)/3=27/(x-1)
⇔(x-1)2=3x27
⇔(x-1)2=81
TH1: x-1=9
⇔x=10
TH2:x-1=-9
⇔x=-8
Vậy x ϵ {-8;10}
a) \(\dfrac{3}{4}-\left(x-\dfrac{2}{3}\right)=1\dfrac{1}{3}\)
\(\dfrac{3}{4}-\left(x-\dfrac{2}{3}\right)=\dfrac{4}{3}\)
\(x-\dfrac{2}{3}=\dfrac{3}{4}-\dfrac{4}{3}\)
\(x-\dfrac{2}{3}=\dfrac{-7}{12}\)
\(x=\dfrac{-7}{12}+\dfrac{2}{3}\)
\(x=\dfrac{-7+8}{12}\)
\(x=\dfrac{1}{12}\)
b) \(\left|\dfrac{1}{3}-x\right|=\dfrac{2}{5}\)
\(\left|-\dfrac{2}{5}\right|=\dfrac{2}{5}\)
\(\left|\dfrac{2}{5}\right|=\dfrac{2}{5}\)
=> \(\dfrac{1}{3}-x=\dfrac{2}{5}\)
=> \(\dfrac{1}{3}-x=\dfrac{-2}{5}\)
TH1: \(\dfrac{1}{3}-x=\dfrac{2}{5}\)
\(x=\dfrac{1}{3}-\dfrac{2}{5}\)
\(x=\dfrac{-1}{15}\)
TH2: \(\dfrac{1}{3}-x=\dfrac{-2}{5}\)
\(x=\dfrac{1}{3}+\dfrac{2}{5}\)
\(x=\dfrac{11}{15}\)
c) \(\dfrac{x-1}{3}=\dfrac{27}{x-1}\)
\(\left(x-1\right)\left(x-1\right)=3\cdot27\)
\(\left(x-1\right)^2=81\)
\(\left(x-1\right)^2=9^2=\left(-9\right)^2\)
TH1: x-1 = 9
x = 10
TH2: x-1 = -9
x = -9 +1
x= -8
Vậy x ϵ { 10 ; -8}
a) 3/4 - (x - 2/3) = 1\(\dfrac{1}{3}\)
3/4 - (x - 2/3) = 4/3
x - 2/3 = 3/4 - 4/3
x - 2/3 = -7/12
x = -7/12 + 2/3
x = 1/12
b)|1/3 - x| = 2/5
|-2/5| = 2/5
|2/5| = 2/5
=> 1/3 - x = 2/5
=> 1/3 -x = -2/5
TH1: 1/3 - x = 2/5
x = 1/3 - 2/5
x = -1/15
TH2: 1/3 - x = -2/5
x = 1/3 + 2/5
x = 11/15
c) (x-1)(x-1) = 3.27
(x-1)2 = 81
(x-1)2 = 92 = (-9)2
TH1: x - 1 = 9
x = 10
TH2: x - 1 = -9
x = -8
a) 3/4 - (x - 2/3) = 1 1/3 b) | 1/3 - x | = 2/5 c)x - 1/3 = 27/x - 1
(x - 2/3) = 3/4 - 1 1/3 1/3 - x = -2/5 áp dụng tính chất tỉ lệ thức,
x - 2/3 = -7/12 hoặc 1/3 - x = 2/5 ta được:
x = - 7/12 + 2/3 x = 11/15 ( x - 1)^2 =3,27
x = 1/12 hoặc x = -1/15. ( x - 1)^2 = 81
x -1 = 9 hoặc x -1 = -9
x = 10 hoặc x = -8
3/4 - (x - 2/3) = 1 1/3
3/4 - x + 2/3 = 4/3
3/4 - x = 4/3 - 2/3
3/4 - x = 2/3
x = 9/12 - 8/12
x = 1/12
b)|1/3-x|=2/5
TH1: 1/3-x=2/5
⇔x=1/3-2/5
⇔x=-1/15
TH2: 1/3-x=-2/5
⇔x=1/3+2/5
⇔x=11/15
Vậy x ϵ {-1/15;11/15}
c)(x-1)/3=27/(x-1)
=>(x-1)^2=3x27
=>(x-1)^2=81
TH1: x-1=9
=>x=10
TH2:x-1=-9
=>x= -8
Vậy x thuộc {-8;10}
3/4 - (x - 2/3) = 1 1/3
3/4 - x + 2/3 = 4/3
3/4 - x = 4/3 - 2/3
3/4 - x = 2/3
x = 9/12 - 8/12
x = 1/12
b)|1/3-x|=2/5
TH1: 1/3-x=2/5
⇔x=1/3-2/5
⇔x=-1/15
TH2: 1/3-x=-2/5
⇔x=1/3+2/5
⇔x=11/15
Vậy x ϵ {-1/15;11/15}
c)(x-1)/3=27/(x-1)
=>(x-1)^2=3x27
=>(x-1)^2=81
TH1: x-1=9
=>x=10
TH2:x-1=-9
=>x= -8
Vậy x thuộc {-8;10}
a.x= 1/12
b.x thuộc {11/15;-11/15}
c.x thuộc {8;-10}
a, x=1/12
b, x=-1/15 và11/15
c, x=82 và 80