Question

135 - 3 . ( x + 1 ) = 30

1005²  . 1005^x = 1005⁷

Answer 1

135 - 3 ( x + 1 ) = 30

3 ( x + 1 ) = 105

x + 1 = 35

x = 34

Answer 2

\(1005^2\cdot1005^x=1005^7\)

\(1005^{2+x}=1005^7\)

=> x + 2 = 7

=> x = 5

Vậy,........

Answer 3

\(135-3.\left(x+1\right)=30\)

\(\Rightarrow3.\left(x+1\right)=105\)

\(\Rightarrow x+1=35\)

\(\Rightarrow x=34\)

\(1005^2.1005^x=1005^7\)

\(\Rightarrow1005^x=1005^7\div1005^2\)

\(\Rightarrow1005^x=1005^{7-2}\)

\(\Rightarrow1005^x=1005^2\)

\(\Rightarrow x=2\)

Answer 4

a)135-3 .(x+1)=30                               b)1005² . 1005^x = 1005⁷

   3.(x+1)=135-30                                     2 . x = 7

    x+1=105:3                                              x = 7:2

    x=35-1                                                     x=\(\frac{7}{2}\)

    x=24

Answer 5

Vội quá

\(1005^x=1005^{7-2}\)

\(\Rightarrow1005^x=1005^5\)

\(\Rightarrow x=5\)

Vậy x = 5

Answer 6

1005\(^x\)=1005\(^7\)−2

⇒1005\(^x\)=1005\(^5\)

⇒x=5