Question

(12x−5)(4x−1)+(3x−7)(1−16x)=81    giúp mik vs

Answer 1

\(\Leftrightarrow48x^2-12x-20x+5+3x-48x^2-7+112x=81\)

\(\Leftrightarrow83x=83\)

=>x=1

Answer 2

\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)

\(\Leftrightarrow48x^2-12x-20x+5+3x-48x^2-7+112x=81\)

\(\Leftrightarrow83x-2=81\)

`<=>83x=83`

`<=>x=1`

Vậy \(S=\left\{1\right\}\)

Answer 3

$\iff 48{}^{}-12x-20x+5+3x-48{}^{}-7+112x=81$

$\iff 83x=83$

=>x=1

Answer 4

$\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81$

$\iff 48{}^{}-12x-20x+5+3x-48{}^{}-7+112x=81$

$\iff 83x-2=81$

$\iff 83x=83$

$\iff x=1$

Vậy $S=\left\{1\right\}$