Question

(1/2+x) (2x-3)=0

Answer 1

\(\left(\dfrac{1}{2}+x\right)\left(2x+3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}+x=0\\2x+3=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\2x=3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{3}{2}\end{matrix}\right.\)

Answer 2

(1/2+x) (2x-3)=0

=> 1/2+x=0 hoặc 2x-3=0

x=-1/2 hoặc x=3/2

Answer 3

`(1/2+x)(2x-3)=0`

TH1: `1/2+x=0`

`=>x=0-1/2`

`=>x=-1/2`

TH2: `2x-3=0`

`=>2x=0+3`

`=>2x=3`

`=>x=3/2`

Vậy `x\in{-1/2;3/2}`