\(\dfrac{-1}{2}=x-\dfrac{1}{6}\)
\(\Rightarrow x=\dfrac{-1}{2}+\dfrac{1}{6}=\dfrac{-3}{6}+\dfrac{1}{6}\)
\(\Rightarrow x=\dfrac{-2}{6}=\dfrac{-1}{3}\)
Vậy \(x=\dfrac{-1}{3}\)
Ta có: \(x-\dfrac{1}{6}=\dfrac{-1}{2}\)
\(\Leftrightarrow x=\dfrac{1}{6}-\dfrac{1}{2}=\dfrac{1}{6}-\dfrac{3}{6}=\dfrac{-2}{6}\)
hay \(x=-\dfrac{1}{3}\)