Question

{1/2+x}+ {1/4 +x} + {1/8 +x} + {1/16+ x} =1

tìm x

Answer 1

\(\left(\frac{1}{2}+x\right)+\left(\frac{1}{4}+x\right)+\left(\frac{1}{8}+x\right)+\left(\frac{1}{16}+x\right)=1\)

         \(\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)+\left(x+x+x+x\right)=1\)

                                                                             \(\frac{15}{16}+4x=1\)

                                                                                          \(4x=\frac{1}{16}\)

                                                                                            \(x=\frac{1}{64}\)

Answer 2

( x + x + x + x ) + ( \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\) ) = 1

x * 4 + \(\frac{15}{16}\) = 1

x * 4 = 1 - \(\frac{15}{16}\)

x * 4 = \(\frac{1}{16}\)

x = \(\frac{1}{16}\) : 4

x = \(\frac{1}{64}\)

Answer 3

\(\left(\frac{1}{2}+x\right)+\left(\frac{1}{4}+x\right)+\left(\frac{1}{8}+x\right)+\left(\frac{1}{16}+x\right)=1\)

\(\Rightarrow=\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}=1\right)\)

\(\Rightarrow=x\times4=1-\frac{15}{16}\)

\(\Rightarrow=x\times4=\frac{1}{16}\)

\(\Rightarrow x=\frac{1}{16}\div4\)

\(\Rightarrow x=\frac{1}{64}\)

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