\(\sqrt{64}+\sqrt{116}-2\sqrt{36}\)
= 8 + 2\(\sqrt{29}\) - 2. 6
= 8 + 2 . 5,39 - 12
= 8 + 10,78 - 12
= 6,78
3.
$\sqrt{x}=2\Leftrightarrow (\sqrt{x})^2=2^2\Leftrightarrow x=4$
4.
$\sqrt{8}-\sqrt{32}+\sqrt{50}=\sqrt{2^2.2}-\sqrt{4^2.2}+\sqrt{5^2.2}$
$=2\sqrt{2}-4\sqrt{2}+5\sqrt{2}=(2-4+5)\sqrt{2}=3\sqrt{2}$
1.
$\sqrt{64}+\sqrt{116}-2\sqrt{36}$
$=\sqrt{8^2}+\sqrt{2^2.29}-2\sqrt{6^2}$
$=8+2\sqrt{29}-2.6=2\sqrt{29}-4$
2.
$\sqrt{45}+\sqrt{20}-\sqrt{5}=\sqrt{3^2.5}+\sqrt{2^2.5}-\sqrt{5}$
$=3\sqrt{5}+2\sqrt{5}-\sqrt{5}=4\sqrt{5}$
Bài 4:
ta có: \(\sqrt{8}-\sqrt{32}+\sqrt{50}\)
\(=2\sqrt{2}-4\sqrt{2}+5\sqrt{2}\)
\(=3\sqrt{2}\)
