Đặt (1.2+2.3+3.4+..+98.99)=a
=>3a= 1.2.(3-0)+2.3.(4-1).....98.99.(100-97)
=>3a=1.2.3-0+2.3.4-1.2.3+...+98.99.100-97.98.99
=>3a=98.99.100
=>a-98.99.100/3=323400
Thay vào,ta được
323400.x/26950=12
=>323400.x=12.26950=323400
=>x=1
6/7:1.5=4/7
\(\left(1.2+2.3+3.4+...98.99\right).x:26950=12\)
\(\Rightarrow\left(\dfrac{98.99.100}{3}\right).x=12.26950\)
\(\Rightarrow98.33.100.x=12.26950\)
\(\Rightarrow x=\dfrac{12.26950}{98.33.100}=\dfrac{1100}{11.100}=1\)
\(\dfrac{6}{7}:1,5=\dfrac{6}{7}:\dfrac{3}{2}=\dfrac{6}{7}.\dfrac{2}{3}=\dfrac{4}{7}\)