Theo bài ra , ta có :
\(\frac{1}{2}+\frac{1}{3}=x:\frac{1}{2012}\)
\(\Rightarrow\frac{5}{6}=x:\frac{1}{2012}\)
\(\Rightarrow x=\frac{1}{2012}\times\frac{5}{6}\)
\(\Rightarrow x=\frac{5}{12072}\)
Vậy \(x=\frac{5}{12072}\)
Chúc bạn học tốt =))
Theo bài ra , ta có :
\(\frac{1}{2}+\frac{1}{3}=x:\frac{1}{2012}\)
\(\Rightarrow\frac{5}{6}=x:\frac{1}{2012}\)
\(\Rightarrow x=\frac{1}{2012}\times\frac{5}{6}\)
\(\Rightarrow x=\frac{5}{12072}\)
Vậy \(x=\frac{5}{12072}\)
Chúc bạn học tốt =))
Giải Pt :
a) \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+........+\frac{1}{x\left(x+1\right)}=\frac{\sqrt{2012-x}+2012}{\sqrt{2012-x}+2013}\)
b) \(\sqrt{2x+3}+\sqrt{x+1}=3x+2\sqrt{2x^2+5x+3}-16\)
giải phương trình: \(\frac{x-1}{2012}+\frac{x-2}{2011}+\frac{x+3}{2010}+...+\frac{x-2012}{1}=2012\)
a, Cho \(A=\sqrt{2012^2+2012^2.2013^2+2013^2}\). CMR A là 1 STN
b, Giải hệ \(\left\{{}\begin{matrix}x^2+\dfrac{1}{y^2}+\dfrac{x}{y}=3\\x+\dfrac{1}{y}+\dfrac{x}{y}=3\end{matrix}\right.\)
Giai he phuong trinh
1) \(\hept{\begin{cases}\left(x^4+1\right)\left(y^4+1\right)=4xy\\\sqrt[3]{x-1}-\sqrt{y-1}=1-x^3\end{cases}}\)
2) \(\hept{\begin{cases}\left(x+\sqrt{x^2+2012}\right)\left(y+\sqrt{y^2+2012}\right)=2012\\x^2+z^2-4\left(y+z\right)+8=0\end{cases}}\)
giải pt ( đặt ẩn phụ)
1. \(x^2+\sqrt{x+2012}=2012\)
2.\(4\cdot\sqrt{\frac{3x+1}{x-1}}+\sqrt{\frac{x-1}{3x+1}}=4\)
3. \(\left(x-3\right)\cdot\left(x+1\right)+4\cdot\left(x-3\right)\cdot\sqrt{\frac{x+1}{x-3}}+3=0\)
Cho \(f\left(x\right)=\frac{x^3}{1-3x+3x^2}\)hãy tính giá trị biểu thức
\(A=f\left(\frac{1}{2012}\right)+f\left(\frac{2}{2012}\right)+...+f\left(\frac{2010}{2012}\right)+f\left(\frac{2011}{2012}\right)\)
Giải phương trình :a,\(\sqrt{1-x}=\sqrt{6-x}-\sqrt{-5-2x}\)
b,\(\sqrt{x^2 +1-2x}+\sqrt{x^2+4-4x}=\sqrt{1+2012^2+\frac{2012^2}{2013^2}}+\frac{2012}{2013}\)
c,\(x^2-x-1=\sqrt{8x+1}\)
Tính: \(\sqrt{2012-2\sqrt{2011}}+1\)
CMR: \(\frac{1}{3}< =\frac{x^2+x+1}{x^2-x+1}< =3\)
Giải phương trình
a) x+y+z=2. \(\left(2\sqrt{x+1}+3\sqrt{y+2}+4\sqrt{z+3}\right)\)
b) \(\frac{16}{\sqrt{x-2012}}+\frac{1}{\sqrt{y-2013}}=10-\sqrt{x-2012}-\sqrt{y-2013}\)