-1/2 + (-1/3) - (-5/4)
= -1/2 - 1/3 + 5/4
= -5/6 + 5/4
= 5/12
-1/2 + (-1/3) - (-5/4)
= -1/2 - 1/3 + 5/4
= -5/6 + 5/4
= 5/12
a,1/3 .(x-2/5)=3/4 b, 7/3:(x-2/3)=4/5 c,1/3.(x-2/5)=4/5 d, 2/3.(x-1/2)-1/4.(x-2/5)=7/3 e,3/7 .(x-2/3)+1/2=5/4.(x-2) f,1/2.(x-3)+1/3.(x-4)+1/4.(x-5)=1/5 g,[2/3.(x-1/2)-4/5]:(x-1/3)=21/5 h, {x-[1/2.(x-3)+11/5]}:(x-1/2)=3/5 i,x.(x-2/5)-(x+2).x+11/4=4/3
a,12 1/3 - (3 3/4 + 4 3/4)
b,3 5/6 + 2 1/6 x 6
c,3 1/2 + 4 5/7 - 5 5/14
d,4 1/2 + 1/2 : 5 1/2
1. (1+1/2).(1+1/2^2).(1+1/2^3)....(1+1/2^100) < 3
2. 1/(5+1)+2/(5^2+1)+4/(5^4+1)+...+ 1024/(5^1024+1) <1/4
3. 3/(1!+2!+3!)+4/(2!+3!+4!)+...+100/(98!+99!+100!) <1/2
1. 3/2 x 4/5 - x = 2/3
2.x x3 1/2=3 1/3 : 4 1/4
3. 5 2/3:x = 3 2/3- 2 1/2
4. 3/2+1/2:x=3 1/2
5.3/4 x x - 1/5=1/5:1/8
1/2-1/3-2/3+1/4+2/4+3/4-1/5-2/5-3/5-4/5+...+1/10+2/10+3/10+...+9/10+10/10
Bài 1:thực hiện phép tính(hợp lí nếu có thể):
1, -5/12 x 2/11 + -5/12 x 9/11 + 5/12
2, -3/5 : 7/5 - 3/5 : 7/5 + 2 3/5
3, 1/2+ 3/4 - ( 3/4 - 4/5)
4, 2/3 + 1/3 x ( -4/9 + 5/6)
5, -3/7 x 5/9 + 4/9 x -3/7 + ( - 2022) ^ 0
6,0,75 - ( 2 1/3 + 0,75) + 3 ^ 2 x ( -1/9)
7, 2 6/7 x [(-7/5 - 3/2 : -5/-4) + ( 3/2)^2]
8,2/7 + 5/7 x ( 3/5 - 0,25 ) x ( -2)^2 + 35%
9, 1 13/15 x 0,75 - ( 11/20 + 25%): 1 2/5
10, ( -2,4 + 1/3 ) : 3 1/10 + 75% : 1 1/2
11.5/3 - 5/7 + 5/9 / 10/3 - 10/7 + 10/9
a) 4 3/8 + 5 2/3 b) 2 3/8 + 1 1/4 + 3 6/7
c) 2 3/8 - 1 1/4 + 5 1/3 d) (5/2 + 1/3) : ( 1 - 1/2)
e) (5/2 - 1/3) x 9/2 - 6/7
1) 3/8-1/5+3/40
2) 5/12+-11/15-49/60
3) (3/8+-3/4+7/12):5/6+1/2
4) 6 và 1/5.(-2/7)+14 và 4/5.(-2/7)
5) 71 và 38/45-(43 và 8/45-1 và 17/45)
6) (3-2 và 1/3+1/4): (4-5 và 1/6+2 và 1/4)
7) 4/9.19 và 1/3-4/9.39 và 1/3
8)(-1/2) mũ 2:1/4-2.(-1/2) mũ 2
9) [6+(1/2) mũ 3-|-1/2|]:3/12
10) 125%.(-1/2) mũ 2: (1 và 5/16-1,5)+2008 mũ 0
11) (2/5) mũ 2 + 5 và 1/2.(4,5-2)+2 mũ 3/-4
- giúp e với ạ!!
cần rất gấp ạ( mong mn giúp vs ạ)
a,-2\3x+1\5=1\10
b,2|1\2x-3\8|-3\2=1\4
c,-5(x+1\5)-1\2(x-2\3)=3\2x-5\6
d,3(x-1\2)- 5(x+3\5)=-x+1\5
e,3\4-2.|2x-0,125|=2
f,2|1\2x-1\3|-3\2=1\4
g,4\5-1\2x=1\10
Tính C=1/2-(1/3+2/3)+(1/4+2/4+3/4)-(1/5+2/5+3/5+4/5)+...+(1/100+2/100+...+99/100)