Đặt
\(S=\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{2003+2005}\)
\(2S=\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{2003+2005}\)
\(2S=\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{2003}-\frac{1}{2005}\)
\(2S=\frac{1}{1}-\frac{1}{2005}=\frac{2004}{2005}\)
\(S=\frac{2004}{2005}.\frac{1}{2}=\frac{1002}{2005}\)
1\1*3+1\3*5+1\5*7+...+1\2003\2005
A=1-3+5-7+...+2001-2003+2005
B=1-2-3+4+5-6-7+8+...+1993-1994
C=1+2-3-4+5+6-7-8+9+...+2002-2003-2004+2005+2006
Mọi người giúp mk nha
A=1+(-2)+3+(-4)+...+2019+(-2020)
B=1+(-3)+5+(-7)+...+2001+(-2003)
C=2-4+6-8+...+1998-2000
D=1-2-3+4+5+6-7-8+9+...+2002-2003-2004+2005+2006
E=1+2-3-4+5+6-7-8+9+...+2002-2003-2004+2005+2006
Tính
S = 0-1=2-3+4-5+6-7+...+2004-2005
S = 1-3+5-7+9-11+...+2005-2007
S = 1-2+3-4+5-6+.. + 2001 - 2002 + 2003
S = 2194.21952195+2195.21942194
Tính các tổng sau
a) A = 1 – 3 + 5 – 7 + … + 2001 – 2003 + 2005. b) B = 1 – 2 – 3 + 4 + 5 – 6 - 7 + 8 + …+ 1993 – 1994.
1-3+5-7+...+2001-2003+2005
1-3+5-7+...+2001-2003+2005
Tính các tổng:
1/ S = 1 - 2 - 3 + 4 + 5 - 6 - 7 + 8 + ...+ 2001- 2002 - 2003 + 2004
2/ S = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + ...+ 2002 - 2003 - 2004 + 2005 + 2006
Tính:
a) 1-3+5-7+...+2001-2003+2005
b) 1-2-3+4+5-6-7+8+...+1993-1994
