\(\dfrac{1}{12}+\dfrac{1}{4}+\dfrac{2}{3}\\ =\dfrac{1}{12}+\dfrac{3}{12}+\dfrac{8}{12}\\ =\dfrac{1+3+8}{12}\\ =\dfrac{12}{12}\\ =1\)
\(\dfrac{1}{12}+\dfrac{1}{4}+\dfrac{2}{3}=\dfrac{1}{12}+\dfrac{1.3}{4.3}+\dfrac{2.3}{3.4}=\dfrac{1+3+6}{12}=\dfrac{12}{12}=1\)
\(\begin{align*} \frac{1}{12} + \frac{3}{12} + \frac{8}{12} &= \frac{1+3+8}{12} \\ &= \frac{12}{12} \\ &= 1 \end{align*}\)